Question

Please answer this question...

Answer 1

$\frac{3 \cos(55) }{7 \sin(35) } - \frac{4( \cos(70). \csc(20) }{7( \tan(5) \tan(25) \tan(65) \tan(85) }$

=3cos(55°)/ 7{sin(90°-55°)} -{4cos(70°).cosec(90°- 70°)}/7{tan(5°) tan(25°) tan(90°-65°) tan(90°-85°)}

=3cos(55°)/7cos(55°)-4{cos(70°).sec(70°)}/7{tan(5°).cot(5°).tan(25°).cot(25°)}

=3/7-4/7

-1/7

That's it
Hope it helped (≧∇≦)b