Question

please answer this question ​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

let the two consecutive positive odd integers be x and (x+2)

ATQ,

${x}^{2} + {(x + 2)}^{2} = 514$

${x}^{2} + {x}^{2} + 4 + 4x = 514$

$2 {x}^{2} + 4x - 510 = 0$

${x}^{2} + 2x - 255 = 0$

${x}^{2} + 17x - 15x - 255 = 0$

$x(x + 17) - 15(x + 17) = 0$

$(x - 15)(x + 17) = 0$

x-15=0 or x + 17 = 0

x =15 or x = -17(neglect)

so,

the two consecutive positive odd integers are 15 and 17