Question

please answer this question

Answer 1

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Answer 2

HELLO DEAR,




x³+ 13x²+ 32x + 20





LET p(x) = x³+ 13x²+ 32x + 20





Put x = –1 in p(x), WE GET




p(–1) = (–1)³+ 13(–1)²+ 32(–1) + 20




=(–1) + 13 + (–32) + 20


= 33 – 33 = 0



HENCE,



(x + 1) IS A FACTOR Of p(x)



Now Divide P(x) With (x + 1),


We Get x²+ 12x + 20



p(x) = (x + 1)(x2+ 12x + 20)





Let's factorize x²+ 12x + 20







=> p(x) = (x + 1)(x2+ 10x + 2x + 20)






= (x + 1)[x(x + 10) + 2(x + 10)]




= (x + 1)(x + 10)(x + 2)



I HOPE ITS HELP YOU DEAR,
THANKS