Question

please answer this question ​

Answer 1

Step-by-step explanation:

Given:-

In a ∆ABC whose vertices are A(2,2) ,B(-4,-4) and C(5,-8).

To find:-

Find the centroid of ∆ABC whose vertices are A(2,2) ,B(-4,-4) and C(5,-8).

Using formula:-

If the vertices of a triangle are (x1,y1),(x2,y2) and (x3,y3) then the centroid of the triangle is

((x1+x2+x3)/3,(y1+y2+y3)/3)

Solution:-

Given vertices of a ∆ABC are

A(2,2) ,

B(-4,-4) and

C(5,-8).

Let they be

(x1,y1)=A(2,2) =>x1=2;y1=2

(x2,y2)=B(-4,-4)=>x2=-4;y2=-4

(x3,y3)=C(5,-8)=>x3=5;y3=-8

now

Centroid of the triangle=G(x,y)

=>((2-4+5)/3,(2-4-8)/3)

=>G(x,y)=(3/3,-10/3)

=>G(x,y)=(1,-10/3)

Answer:-

The centroid of the triangle ABC is (1,-10/3)

Answer 2

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Explanation:

Given :

Vertices of ∆ABC=A(2,2) ;B(-4,-4) &C(5,-8)

TO FIND :

Centroid of the triangle

What is centroid..??

Centroid is a point which is located in the centre of the Traingle formed by intersection of the median.It is equidistant from all the 3 vertices.

Formula for finding centroid of a triangle :-

$\bold{\boxed{x = \frac{x1 + x2 + x3}{3} }}$

$\bold{\boxed{y = \frac{y1 + y2 + y3}{3}}}$

x=2;X2=-4 &X3=5

y=2;y2=-4 &y3=-8

$x = \frac{2 + ( - 4) + 5}{3} = \frac{ - 2 + 5}{3} = 1$

$y = \frac{2 + ( - 4) + ( - 8)}{3} = \frac{ - 2 - 8}{3} = - \frac{10}{3}$

Therefore,the centroid of the Traingle∆ABC is (1,-10/3)