the radius of the earth is about 6370 km. an object of mass 30kg is taken to a height of 230 kg above the surface of the earth. What is th acceleration of gravity at this height.
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Explanation:
g at height h = g at surface ( 1 - (2h/R)), where R is the radius of the earth
g at 230 Km = 9.8 ( 1 - 460/6370) = 9.8 (0.928) = 9.1 m/s^2
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