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it is hard question chhbc
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Let's begin
Step-by-step explanation:
ABC is an isosceles triangle in which AB = AC and AD is the bisector of <BAC.
In triangles ADB and ADC
AB = AC (given)
<B = <C ( as adjacent sides are equal AB = AC. then the angles of adjacent sides will also be equal)
AD is common.
<ADB = <ADC = 90 degrees , as AD is Bisector so 90 degree angle is formed.
1) Three pairs equal in triangles are AB=AC, angle B = angle C , <ADB = <ADC = 90 degrees .
2) Therefore triangles ABD and ACD are congruent as the above written parts of triangles are equal.
3) <B = <C ( as adjacent sides are equal AB = AC. then the angles of adjacent sides will also be equal)
These are the reasons, hope this helps!!!!
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