Question

please answer this question

Answer 1

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Answer 2

Given 1651m + 2032n.

2032> 1651


(1) 2032 = 1651 * 1 + 381

The remainder is not equal to 0. Use division algorithm to 1651 and 381.


(2) 1651 = 381 * 4 + 127

The remainder is not equal to 0. use division algorithm to 318 and 127.


(3) 381 = 127 * 3 + 0.

The remainder is 0.

Therefore the HCF of 1651 and 2032 = 127.


Now,

127 = 1651 - 381 * 4

       = 1651 - (2032 - 1651) * 4

       = 1651 - 2032 * 4 + 1651 * 4

       = 1651(5) - 2032(4)

       = 1651(5) + 2032(-4)

It is in the form of 1651(m) + 2032(n).

Therefore m = 5 and n = -4.



Hope this helps!