Question

please answer this question ​

Answer 1

Answer:

Angle ACB = 38 DEGREE

Angle DAC = 38 DEGREE

Angle ADC = 104 DEGREE.

Step-by-step explanation:

ABCD is Rhombus (Given)

AB = BC

∠BAC = ∠ACB (∠s opp. to equal sides)

But ∠BAC = 38° (Given)

∠ACB = 38°

In ∆ABC,

∠ABC + ∠BAC + ∠ACB = 180°

∠ABC + 38°+ 38° = 180°

∠ABC = 180° – 76° = 104°

But ∠ABC = ∠ADC (opp. ∠s of rhombus)

∠ADC = 104°

∠DAC = ∠DCA ( AD = CD)

∠DAC = \frac { 1 }{ 2 } [180° – 104°]

∠DAC = \frac { 1 }{ 2 } x 76° = 38°

Hence (i) ∠ACB = 38° (ii) ∠DAC = 38° (iii) ∠ADC = 104°

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Answer 2

Answer:

Your Answer is in picture

< ACB = 38⁰

< DAC = 38⁰

< ADC = 104⁰

Explanation:

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