Question

please answer this question

Answer 1

Hey Sowmiya!!

Here, we are given the following data:

Present age of Ashu = $x$ years
Present age of Mrs Veena = $x^2$ years

After 5 years, we will have :

Age of Ashu = $x+5$ years
Age of Mrs Veena = $x^2+5$ years

We are given that 5 years from present, age of Mrs Veena is three times that of Ashu.

So, we can write the equation as:
$(x^2+5)=3\times (x+5) \\ \\ \implies x^2+5 = 3x+15 \\ \\ \implies x^2-3x-10=0$

Here, the product of first and last terms of the quadratic equation is -10. Also, middle term is -3. So, we can factorise the whole quadratic equation as shown:


$x^2 -3x-10=0 \\ \\ \implies x^2-5x+2x-10=0 \\ \\ \implies x(x-5)+2(x-5)=0 \\ \\ \implies (x-5)(x+2)=0 \\ \\ \implies x-5=0 \, \, OR \, \, x+2=0 \\ \\ \implies x=5 \, \, OR \, \, x=-2.$

But, x is the present age of Ashu. Age cannot be negative.


So, 
$\boxed{x=5}$

Thus, we have:

Present age of Ashu = $x$ = 5 years

Present age of Mrs Veena = $x^2$ = 25 years



Hope it helps
Purva
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