Question

Please answer this question

Answer 1

Answer:

girl nte indu prakash misra I have a good day I am leaving the office of temperature and humidity is the best of all the best regards the happy hour at least a few I will be in the hall with big attributes of the triangle I am leaving for work and altitude of the given instructions to see you soon size and shape of the triangle I will be in the alveoli suitable for adults and altitude of temperature

Answer 2

Given:-

• Side of the Square = 14cm.

To Find:-

• Area of Shaded Region.

Solution:-

☞ Actually we cannot say that the given figure is a square, but as for the truth of our perceive we can say all sides are equal and all angles are 90°. Hence, it is a Square.

$\boxed{\sf{\star\;Area\;of\; Square = Side×Side}}$

$→\;{\sf{14×14}}$

$→\;{\sf{(14)²}}$

$→\;\red{\sf{196cm²}}$

• Area of Square = 196cm²

☞ Here Side of the Square is the diameter of the semicircle.

$\boxed{\sf{\star\; Radius = \frac{Diameter}{2}}}$

→ R = d/2

$→\;{\sf{\frac{14}{2}}}$

$→\;{\sf{7cm}}$

• Radius = 7cm

☞ WKT, Two Semicircles forms a Complete Circle.

$\boxed{\sf{\star\;Area\;of\; Circle = {\pi}r²}}$

$→\;{\sf{\frac{22}{7}×(7)²}}$

$→\;{\sf{\frac{22}{7}×7×7}}$

$→\;{\sf{22×7}}$

$→\;\red{\sf{154cm²}}$

• Area of Two Semicircles = 154cm²

→ Area of Shaded Region = Area of Square - Area of Two Semicircles.

$→\;{\sf{196-154}}$

$→\;{\sf{42cm²}}$

• Area of Shaded Region ➝ $\red{\bold{42cm²}}$

$\Large{✓}$

Hope It Helps You ✌️