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side of equilateral triangle = 12cm
perimeter of equi. triangle
= 3 × side = 3 × 12 = 36cm
diagonal of square = 2√2cm
√2 × side = 2√2cm
side = 2cm
perimeter of square
= 4 × side = 4 × 2 = 8cm
Given that ,
circumference of circle
= perimeter of equi.triangle + perimeter of square
2πr = 36 + 8 = 44
2πr = 44
r = 44 × 7/ 2 × 22
r = 7cm
radius of circle = 7cm
area of circle = πr^2 = 22 × (7)^2/ 7
= 154cm^2
Answer: area of circle = 154cm^2
perimeter of equi. triangle
= 3 × side = 3 × 12 = 36cm
diagonal of square = 2√2cm
√2 × side = 2√2cm
side = 2cm
perimeter of square
= 4 × side = 4 × 2 = 8cm
Given that ,
circumference of circle
= perimeter of equi.triangle + perimeter of square
2πr = 36 + 8 = 44
2πr = 44
r = 44 × 7/ 2 × 22
r = 7cm
radius of circle = 7cm
area of circle = πr^2 = 22 × (7)^2/ 7
= 154cm^2
Answer: area of circle = 154cm^2
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