Question

Please answer this question

Answer 1

Answer:

Let $x^2-5=0$:

$x^2=5; x=\±\sqrt{5}$

∴ a=√5, b=-√5

To form a quadratic polynomial:

(x-z₁)(x-z₂)=0 where y=0, z₁ and z₂ are zeroes of this quadratic equation

(x-(1+a))(x-(1+b))=0

(x-1-a)(x-1-b)=0

(x-1-√5)(x-1+√5)=0

After the expansion, the result is:

$x^2-2x-4$=0

Writing in polynomial form gives:

y=$x^2-2x-4$

Hope this helps :)

Step-by-step explanation: