Question

please answer this question​

Answer 1

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Answer 2

Answer:

57.73 m/min

Step-by-step explanation:

Let the speed of the boat be 'x' metre per minute.

Let AB be the lighthouse and C,D be the positions of boat such that AB = 100 m,CD = 2x.

∠ADB = 30° and ∠ACB = 60°.

(i) In ΔADB:

AB/DB = tan 30°

⇒ 100/DB = (1/√3)

⇒ BD = 100√3

(ii) In ΔABC:

(AB/BC) = tan 60°

⇒ 100/BC = √3

⇒ BC = (100/√3)

∴ CD = BD - BC

⇒ 2x = (100√3) - (100/√3)

⇒ 2x = (300 - 100)/√3

⇒ 2x = 200/√3

⇒ x = 100/√3

⇒ x = 100/1.732

⇒ x = 57.73 m/min.

Therefore, Speed of the boat is 57.73 metre per minute.

Hope it helps!