Question

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Answer 1

Given,

PQ || ST, ∠PQR = 110° and ∠RST = 130°

Construction,

line XY parallel to PQ and ST is drawn.

∠PQR + ∠QRX = 180° (Co. int. angle)

⇒ 110° + ∠QRX = 180°

⇒ ∠QRX = 70°

Also,

∠RST + ∠SRY = 180° (Co. int. angle)

⇒ 130° + ∠SRY = 180°

⇒ ∠SRY = 50°

Now,

∠QRX +∠SRY + ∠QRS = 180°

⇒ 70° + 50° + ∠QRS = 180°

⇒ ∠QRS = 60°