please answer this question and tell me the procedure
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Molarity can be defined as
M = n/V
where; M = Molarity, n= no. of moles of solute present in the V litre of solution.
Now, if you dilute the solution by adding a solvent say water, V ( volume of the solution) will change and so will molarity M but the number of moles of the solute n present in the solution after addition of water will not change.
Thus we have
n = MV = constant ( On dilution )
Now we can use the above expression to calculate the molarity of a solution after dilution. We have now for two different conditions
M1V1 = M2V2
where; M1 = Molarity of the solution before dilution, V1 = Volume of the solution before dilution, M2 = Molarity of the solution after dilution and V2 = Volume of the solution after dilution.
Note : The terminology of “ solute”, “solution” and “solvent” is very important while you are dealing with the problems related to concentration.
So now you can put related values in the above equation :
1 x 100 = M2 x 1000
Note : 1 L = 1000 mL
M2 = 0.1
The the molarity of the solution after dilution will be 0.1.
Hope you got the answer of your question.
M = n/V
where; M = Molarity, n= no. of moles of solute present in the V litre of solution.
Now, if you dilute the solution by adding a solvent say water, V ( volume of the solution) will change and so will molarity M but the number of moles of the solute n present in the solution after addition of water will not change.
Thus we have
n = MV = constant ( On dilution )
Now we can use the above expression to calculate the molarity of a solution after dilution. We have now for two different conditions
M1V1 = M2V2
where; M1 = Molarity of the solution before dilution, V1 = Volume of the solution before dilution, M2 = Molarity of the solution after dilution and V2 = Volume of the solution after dilution.
Note : The terminology of “ solute”, “solution” and “solvent” is very important while you are dealing with the problems related to concentration.
So now you can put related values in the above equation :
1 x 100 = M2 x 1000
Note : 1 L = 1000 mL
M2 = 0.1
The the molarity of the solution after dilution will be 0.1.
Hope you got the answer of your question.
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