Chemistry, asked by Anish1269, 1 year ago

please answer this question and tell me the procedure

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Answered by gauravgh
1
Molarity can be defined as

M = n/V

where; M = Molarity, n= no. of moles of solute present in the V litre of solution.

Now, if you dilute the solution by adding a solvent say water, V ( volume of the solution) will change and so will molarity M but the number of moles of the solute n present in the solution after addition of water will not change.

Thus we have

n = MV = constant ( On dilution )

Now we can use the above expression to calculate the molarity of a solution after dilution. We have now for two different conditions

M1V1 = M2V2

where; M1 = Molarity of the solution before dilution, V1 = Volume of the solution before dilution, M2 = Molarity of the solution after dilution and V2 = Volume of the solution after dilution.

Note : The terminology of “ solute”, “solution” and “solvent” is very important while you are dealing with the problems related to concentration.

So now you can put related values in the above equation :

1 x 100 = M2 x 1000

Note : 1 L = 1000 mL

M2 = 0.1

The the molarity of the solution after dilution will be 0.1.

Hope you got the answer of your question.

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