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Answer:
A rain drop of radius= 2mm
falls from a height of = 500m
(Given)
2×10-3 m
Density of water , p= 10 3 kgm -3
The mass contained in the rain drop, m= pv
➡ 3 4 × 3.141× (2×10-3)
3×10 3 kg
Gravitational force experienced by the rain drop,= F mg ➡ 3 4 × 3.141 ×(2× 10-3)
3×10 3×9.8 N
The work done by the gravity on the drop is given by: W 1=Fs= 3 4×3.14×(2×10 3)
3×10 3× 9.8×250=0.082 J
The work done on the drop in the second half of the ✈journey will be same as that in the first half
.
. . W 2
= 0.082 J
The total energy of the drop remains conserved during it's motion.
The total energy at the top E T=Mgh+0
=4/3×3.14×(10-3)
3×10 3× 500×10-5
=0.164 J
Due to the presence of a resistive force the drop hits hits the ground with a velocity of m/s.
Total energy in the ground: E G= 2 1 mv 2+01/4×3×3.141 × (2×10-3)
3×10 3 × 9.8×10 2
= 1.675×10-3 J
So., the work done by the resistive force=E G -E T
=0.162 J
Explanation:
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Answer: A rain drop of radius= 2mm
falls from a height of = 500m
(Given)
2×10-3 m
Density of water , p= 10 3 kgm -3
The mass contained in the rain drop, m= pv
➡ 3 4 × 3.141× (2×10-3)
3×10 3 kg
Gravitational force experienced by the rain drop,= F mg ➡ 3 4 × 3.141 ×(2× 10-3)
3×10 3×9.8 N
The work done by the gravity on the drop is given by: W 1=Fs= 3 4×3.14×(2×10 3)
3×10 3× 9.8×250=0.082 J
The work done on the drop in the second half of the ✈journey will be same as that in the first half
.
. . W 2
= 0.082 J
The total energy of the drop remains conserved during it's motion.
The total energy at the top E T=Mgh+0
=4/3×3.14×(10-3)
3×10 3× 500×10-5
=0.164 J
Due to the presence of a resistive force the drop hits hits the ground with a velocity of m/s.
Total energy in the ground: E G= 2 1 mv 2+01/4×3×3.141 × (2×10-3)
3×10 3 × 9.8×10 2
= 1.675×10-3 J
So., the work done by the resistive force=E G -E T
=0.162 J