Question

Please answer this question as soon as possible.

Answer 1

$\boxed{\boxed{\mathsf{10, 40}}}$
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$\underline{\underline{\huge\mathfrak{ANSWER}}}$

Let age of daughter be $\mathbf{x}$
and the age of mother be $\mathbf{y}$

$\underline{A.T.Q,}$

y - 5 = 7(x - 5)

$\mathsf{\Longrightarrow}$ y - 5 = 7x - 35

$\mathbf{\Longrightarrow -7x + y + 30 = 0 ----(1)}$

Also,

y + 5 = 3(x + 5)

$\mathsf{\Longrightarrow}$ y + 5 = 3x + 15

$\mathbf{\Longrightarrow -3x + y - 10 = 0----(2)}$

Subtracting equation (1) by equation (2), we get

$\mathsf{\Longrightarrow -4x = 40}$

$\mathbf{\Longrightarrow x = -10}$

$\underline\text{Since, age can never be negative,} \\ \underline\text{We will take the numerical value of -10.}$
|-10| = 10

Hence, $\boxed{\mathbf{x = 10}}$

Substituting value of $\bf{x}$ in equation (2) we get,

-3(10) + y -10 = 0

$\mathsf{\Longrightarrow -30 + y - 10 = 0}$

$\mathsf{\Longrightarrow y - 40 = 0}$

$\mathsf{\Longrightarrow}$ $\boxed{\mathbf{y = 40}}$
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$\large\boxed{\large\boxed{\large\boxed{\large\mathbb{THANKS}}}}$

$\huge\mathbf{\# Be Brainly}$