Question

please answer this question as soon as possible with correct explanation in notebool

Answer 1

let AB = 2x and BC = 2y
then using Pythagoras theorem we get
( AB) ^2 + ( BC) ^2 = 25
4X^2 + 4 Y^2 = 25 ...........(1)
(AB)^2 + ( BD) ^2 = 45/4
4x^2 + y^2 = 45/4 ........(2)
substract eq2 from EQ 1 we get
3 y^2 = 55/4
y^2 = 55/12
put the value of Y^2 in EQ 2 we get
4x^2 = 80/12
x^2 = 20/12
now in triangle BEC
(CE) ^2 = (BE)^2 + ( BC)^2
(CE)^2 = X^2 + 4Y ^2
( CE) ^2 = 20/12 + 4*55/12 = 240/12 = 20
( CE) = √20 = 2√5 cm

Answer 2

Answer:

CE = 2√5 cm

Step-by-step explanation:

In the attachment.. Hope it's helpful..