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Divide 243 into three parts such that half of the first part, one third of the second part and one fourth of the third part are all equal.
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Let the three divided numbers be a,b and c.
a+b+c=243
a/2=b/3=c/4
b=3a/2
c=2a
a+b+c=243
a+3a/2+2a=243
3a+3a/2=243
6a+3a=486
a=54
b=3a/2=81
c=2a=108
The three divided parts are 54, 81 and 108
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