Question

please answer this question..


don't give the unless answer, I Report it..​

Answer 1

Answer:

Here is the solution

Explanation:

Prove that sin x + sin 3x COS X + Cos 3x = tan 2x

Taking L.H.S. sin x + sin 3x COS X + cos 3x

We solve sin x + sin 3x & cos x + cos 3x seperately

sin x + sin 3x

x+y Using sin x + sin y = 2 sin *+ Putting x=x & y = 3x COS x-y 2

= 2 sin (x+³x) cos (*=³*) 2

= 2 sin (1) cos (-2³)

= 2 sin 2x cos(-x)

COS X + cos 3x

x+y x-y Using cos x + cos y = 2 cos COS 2 Putting x= x & y = 3x 2

= 2 cos • (x+³x) cos (5x=³x) 2 COS 2

= 2 cos (4x) COS

= 2 cos 2x cos (-x)

Now

sin x + sin 3x cos x + cos 3x

2 sin 2x cos(-x) 2 cos 2x cos(-x) sin 2x cos 2x

= tan 2x

= R.H.S

Hence L.H.S = R.H.S

Hence proved

Answer 2

Answer:

you got the answer but other