Question

please answer this question don't spam​

Answer 1

Answer:

P(x)=x(x−2)(x+3)

∴ To find zeroes,

P(x)=0

∴(x)(x−2)(x+3)=0

∴x=0 OR x−2=0 OR x+3=0

∴x=0 OR x=2 OR x=−3

∴ value of x is 0,2,−3

Hope it helps you!!

Answer 2

Explanation:

x² - (-2)² - 2 (x)( -2) - x² + (2)²+ 2(x)(2) = 0

x² - 4 + 4x - x² + 4 + 4x = 0

8x = 0

x = 0