Math, asked by 4566amirtha, 1 month ago

please answer this question fast​

Attachments:

Answers

Answered by Anonymous
16

Given :

Find value of equation :

F(x) = x²- 2x + 2

If value of x :

(i) X = 1

(ii) X = 0

(iii) X = 2

(iv) X = -2

(v) X = -3

(vi) X = 3

 ̄ ̄ ̄ ̄ ̄ ̄ ̄ ̄ ̄ ̄ ̄ ̄

Solution :

F(1) = x²- 2x + 2

{\dashrightarrow{\bf{\red{(i)X = 1}}}}

{\leadsto{\sf{P(1) = (1)²- 2(1) + 2}}}

{\leadsto{\sf{P(1) = 1 - 2 + 2}}}

{\leadsto{\sf{P(1) = ( - 1 )+ 2}}}

{\large{\green{:{\mapsto{\underline{\boxed{\bf{P(1) = -3}}}}}}}}

{\dashrightarrow{\bf{\red{(ii)X = 0}}}}

{\leadsto{\sf{P(0) = (0)²- 2(0) + 2}}}

{\leadsto{\sf{P(0) =  0 - 0 + 2}}}

{\large{\green{:{\mapsto{\underline{\boxed{\bf{P(0) = 2}}}}}}}}

{\dashrightarrow{\bf{\red{(iii)X = 2}}}}

{\leadsto{\sf{P(2) = (2)²- 2(2) + 2}}}

{\leadsto{\sf{P(2) =  4 - 4 + 2}}}

{\large{\green{:{\mapsto{\underline{\boxed{\bf{P(2) = 2}}}}}}}}

{\dashrightarrow{\bf{\red{(iv)X =  - 2}}}}

{\leadsto{\sf{P( - 2) = ( - 2)²- 2( - 2) + 2}}}

{\leadsto{\sf{P(2) = ( -  4 )-( -  4) + 2}}}

{\large{\green{:{\mapsto{\underline{\boxed{\bf{P( - 2) = 2}}}}}}}}

{\dashrightarrow{\bf{\red{(v)X =  - 3}}}}

{\leadsto{\sf{P( - 3) = ( - 3)²- 2( - 3) + 2}}}

{\leadsto{\sf{P( - 3) = ( -  9 )-( -  4) + 2}}}

{\leadsto{\sf{P( - 3) = (  5)+ 2}}}

{\large{\green{:{\mapsto{\underline{\boxed{\bf{P( - 3) = 7}}}}}}}}

{\dashrightarrow{\bf{\red{(vi)X =   3}}}}

{\leadsto{\sf{P( 3) = ( 3)²- 2( 3) + 2}}}

{\leadsto{\sf{P( 3) =   9 -6 + 2}}}

{\leadsto{\sf{P( 3) =   3 + 2}}}

{\large{\green{:{\mapsto{\underline{\boxed{\bf{P(3) = 5}}}}}}}}

So,

✰Value of X = 1 = -3

✰Value of X = 0 = 2

✰Value of X = 2 = 2

✰Value of X = -2 = 2

✰Value of X = -3 = 7

✰Value of X = 3 = 5

 ̄ ̄ ̄ ̄ ̄ ̄ ̄ ̄ ̄ ̄ ̄ ̄

Similar questions