Math, asked by aditya4080, 1 year ago

Please answer this question fast....

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Answers

Answered by Muthu2004
1

given : ABCD is parallelogram

DQ = QP = PB

TO PROVE :

CQ ║AP

PROOF:

In ΔADP and ΔCBQ

AD = BC [ opp. side of parallelogram]

DQ = BP - EQN 1

QP =QP - EQN 2

ADD EQN 1 AND EQN 2

DQ+QP = BP+QP

DP = BP

∠ADP =∠CBQ [ Alternate angle of parallelogram]

∴ΔADP ≅ ΔCBQ

∠APD = ∠BQC [CPCT]

If alternate angles are equal.

∴CQ ║AP


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