Question

prove that tan -1(1) + tan-1(2) + tan-1(3) = pie.

Answer 1

$tan \: invers \: o \: ka \: maan \: \pi \: or \: 0 \: hota \: he$

Answer 2

Answer:

Tan -1 (1) + tan - (2) + tan - 1(3) = pie

Tan -1 [x+y+z-xyz]/ (1 - xy - yz -zx)

Tan -1 [1 + 2 +3 - 1 × 2 × 3]/ [1 - 1 × 2 - 2 × 3 - 3 × 1]

Tan - 1 [6- 6 ]/[ 1 -2 - 6 -3]

Tan - 1 [ 0/ - 10]

Tan - 1 = 0

Tan 0 = pie

Step by-step explanation: