Chemistry, asked by GarvitMishra, 1 year ago

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Answered by QwertyPs
1
In HNO3
Mass of H = 1u
Mass of N = 14u
Mass of O = 16u
Therefore, Mass of HNO3 = 1x1 + 14x1 + 16x3
1 + 14 + 48 = 63
Mass = 63u
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