Math, asked by GENIUSNo001, 1 year ago

Please answer this question fast​

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Answered by Nitin2112
0

AD is median, So DB=DC.

AB^2=EA^2+BE^2

AC^2=EA^2+EC^2  

Adding both,  

AB^2+AC^2 = 2 EA^2+BE^2+CE^2  

= 2(AD^2-ED^2)+(DB-ED)2+(DC+ED)2  

= 2 AD^2-2 ED^2+DB^2+ED^2-2 BD.ED+DC^2+ED^2+2 CD.ED  

= 2 AD^2+DB^2+CD^2  

= 2(AD^2+ DB^2)


simrankaur86: your answer is wrong bro
simrankaur86: ABD is not a right angled triangle
simrankaur86: so you can't apply Pythagoras in it
Nitin2112: I changed it
simrankaur86: hmm
simrankaur86: ab thik hai
Nitin2112: Ok
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