please answer this question fast...
if tana=3/4 then find the value of cos^2A-sin^A
Answers
Answered by
3
Answer:
Step-by-step explanation:
cos^A = 16/25
sin^A = 9/25
therefore, 16/25-9/25
=16-9/25
=7/25
Answered by
2
tanA=3/4 = p/b
p=3, b=4, h=?
h=√p^2 + b^2
= √3^2 + 4^2
= √ 9 + 16 = √25 = 5
cos^2A - sin^2A
(b/h)^2 - (p/h)^2
(4/5)^2 - (3/5)^2
16/25 - 9/25 = 7/25
p=3, b=4, h=?
h=√p^2 + b^2
= √3^2 + 4^2
= √ 9 + 16 = √25 = 5
cos^2A - sin^2A
(b/h)^2 - (p/h)^2
(4/5)^2 - (3/5)^2
16/25 - 9/25 = 7/25
sanjanapachehre26:
thanks
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