please answer this question fast.
six paving stones are arranged in a square array as shown in the figure. If each stone has a length 20 cm greater than its width, find
(a)the dimensions of each stone
(b) the area of the ground space that stones are occupying
(c) the perimeter of the same ground space
Answers
Answer: 1) l = 60cm, w = 40cm
2) 14400cm^2
3) 480cm
Step-by-step explanation:
1) Since, the array formed is of square shape.
So, all sides must be equal.
We have,
Length of array = (x+20)+(x+20) = 2x+40
Width of array = x+x+x = 3x
Now,
Length = Width
=> 2x+40=3x
=> x= 40cm
That is,
Length = 2x+40= 120cm
Width = Length = 120cm=Side
2) Area of ground space stones occupied = Area of array =
Area of square = Side * Side
= 120x 120
=14400cm^2
3) Now,
Perimeter of square array = 4 x Side = 4*120 = 480cm
Answer:
40 * 60 cm²
1.44 m²
4.8 m
Step-by-step explanation:
six paving stones are arranged in a square array as shown in the figure. If each stone has a length 20 cm greater than its width
Total Length = 3x cm
Total Width = 2(x + 20) = 2x + 40 cm
as it is a sqaure
so Total Length = Total Width
=> 3x = 2x + 40
=> x = 40
Dimension of each stone = 40 * 60 cm²
Total Length = Total Width = 120 cm = 1.2 m
the area of the ground space that stones are occupying = 1.2 * 1.2 = 1.44 m²
the perimeter of the same ground space = 4 * 1.2 = 4.8 m