Question

Please answer this question - Find a quadratic polynomial whose zeroes are -9 and -1/9.

Answer 1

Hey friend here is your answer!!☺️☺️☺️


We will find sum and product of these zeroes

To form a quadratic polynomial= k ( x sq - Sx + P) here S is sum and P is product.

Sum of zeroes= - 9 + (-1/9)
= -82/9

Product of zeroes = -9 × (-1/9)
= 1

So putting the values of S and P

quadratic polynomial= k{ x sq - (-82/9)x + 1}
now we will take LCM of bracket which would be the value of k
So,
k ( 9 x sq + 82x + 9/9)
so the quadratic polynomial is 9 x sq + 82 x + 9
and k = 9



☺️☺️☺️hope it helps☺️☺️☺️

Answer 2

Step-by-step explanation:

α = -9   β = -1/9

quadratic polynomial

= k {x ²- (α + β)x + αβ}

= k { x² - (-9 - 1/9)x -9 x -1/9}

= k { x² - (-19/9)x + 1}

= k { x² + 19/9 x + 1}

when k = 1

the quadratic polynomial is x² + 19/9 x + 1

Hope it helps!!

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