please answer this question..Find x,y,z.
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z =60 degree ,x=80 degree ,y=60degree
Aravinthan31:
it simple
but how???
I got it as x=120,y=30,z=60
ya...
in my Textbook answer is given as x-120 y-30 z-90
how u know the method
ya. z=90...
sorry for wrong answer
oh.. it's fine
coz error is human
Answered by
1
I have given Names to the points as shown in the figure
In tri.ABD is a equilateral triangle
All Angles are Equal
say a,3a=180°,a=60°
In tri. ADC,AD=DC
so∠DAC=∠DCA=y
So z=60° + y
∠BDA+x=180° (∵ BC is a line)
x=120°
Using angle sum property on tri.ADC
x+2y=180°
2y=180-120=60°
y=30°
Also z=60°+y=60°+30°=90°
So,z=90°
In tri.ABD is a equilateral triangle
All Angles are Equal
say a,3a=180°,a=60°
In tri. ADC,AD=DC
so∠DAC=∠DCA=y
So z=60° + y
∠BDA+x=180° (∵ BC is a line)
x=120°
Using angle sum property on tri.ADC
x+2y=180°
2y=180-120=60°
y=30°
Also z=60°+y=60°+30°=90°
So,z=90°
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Thank you so much.
No problem
wow...
now whats that supposed to mean chikku16
Feels good to help tho
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