Question

Please answer this question friends

Answer 1

Answer:

(Please mark as Brainliest)

2) 5

Step-by-step explanation:

Let,  x = $\sqrt{5\sqrt{5\sqrt{5\sqrt{5....} } } }$

Squaring on both sides, we get

$x^{2} = 5(\sqrt{5\sqrt{5\sqrt{5\sqrt{5....} } } })\\x^{2} = 5x$

=> $=> x^{2} -5x = 0\\=> x(x-5)=0\\\\ (x-5)=0\\Therefore x = 5$

Answer 2

Let √5√5√5√5........ = x

x = √5√5√5√5......

Squaring on both sides

x² = (√5√5√5√5.....)²

x² = 5(√5√5√5.....)

x² = 5x

we know that, √5√5√5√5 = x

x²-5x = 0

x(x- 5) = 0

x -5 = 0/x

x -5 = 0

x = 5.

hope it helps you....