History, asked by StrongGirl, 9 months ago

The Rajya Sabha passed ‘The Mineral Laws (Amendment) Bill, 2020’, which proposes to commercialise the mining of which mineral?
Iron
Bauxite
Gold
Coal

Answers

Answered by PADMINI

0

The Rajya Sabha passed ‘The Mineral Laws (Amendment) Bill, 2020’, which proposes to commercialize the mining of "coal".

Explanation:

Recently, The Rajya Sabha passed The Mineral Laws (Amendment) Bill, 2020.

The Bill proposes amendments to the Mines and Mineral Act 1957 and The Coal Mines Act, 2015.

This bill was passed by Lok Sabha on 6th March 2020. It will open a new era in the Indian coal & mining sector especially to promote Ease of Doing Business.

Answered by Joy369

0

Answer:coal

Explanation:be is a non renewable energy we have used most of it for electricity

Previous Question

Next Question

Similar questions

Science, 4 months ago

what is difference between communicable and non communicable diseases short answer ...

Math, 4 months ago

In each case write down the rational my whose numerator and denominator are respectively as under (-3)*2 and 15- 8...

Math, 4 months ago

Ram got 8 marks more than Shyam in examination Anil got 4 Marks more than RAM in the same examination if all three of them got 128 marks together as a total,Ram's marks would be,,, plzz tell me what called these types of questions...

English, 9 months ago

name the games which can be played with friends in this long holiday season...

History, 9 months ago

explain the role of nehru in non aligned movement...

Geography, 11 months ago

Draw a parallel between medieval towns and modern day settlements...

Physics, 11 months ago

At what angle must the two forces (x + y) and (x – y) act so that the resultant may be $\sqrt{(x^{2} + y^{2})}$ ? (a) $\cos^{-1}[-(x^{2} + y^{2})}/{2(x^{2} - y^{2})}]$ (b) $\cos^{-1}[-2{(x^{2} - y^{2})}/{(x^{2} + y^{2})}]$ (c) $\cos^{-1}[-{(x^{2} + y^{2})}/{(x^{2} - y^{2})}]$ (d) $\cos^{-1}[-{(x^{2} - y^{2})}/{(x^{2} + y^{2})}]$ ...

Physics, 11 months ago

For any two vectors $\vec{A}\ and\ \vec{B},\ if\ \vec{A}.\vec{B}=|\vec{A}\ \times\ \vec{B}|$ , the magnitude of $\vec{C} = \vec{A} + \vec{B}$ is (a) A + B (b) $\sqrt{A^{2}+B^{2}+\sqrt{2}AB}$ (c) $\sqrt{A^{2}+B^{2}}$ (d) v $\sqrt{A^{2}+B^{2}+\frac{AB}{\sqrt{2}}}$ ...