Question

Please answer this question guys..... please correct answer...

Vry important..

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Answer 1

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$\color{red}\huge{\underline{\underline{\mathfrak{Question:-}}}}$

A figure is given and we have to find the angles named x and y.

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$\color{blue}\huge{\underline{\underline{\mathfrak{Answer}}}}$

• x=80°
• y=60°

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$\color{orange}\huge{\underline{\underline{\mathfrak{Solution:-}}}}$

${\blue{\bold{\text{In triangle AEC}}}}$

Sum of all interior angles is 180°[Angle sum property]

So,

50°+30°+angle AEC=180°

80°+angle AEC=180°

Angle AEC=180°-80°

Angle AEC=100°.........(1)

${\blue{\bold{\text{By linear pair}}}}$

Angle AEC+Angle AEB=180°

100°+x°=180° [From eqn (1)]

x°=180°-100°

x°=80°

${\blue{\bold{\text{Now}}}}$

${\blue{\bold{\text{In triangle BDC}}}}$

${\blue{\bold{\text{Angle D is given 90°}}}}$

${\blue{\bold{\text{By angle sum property}}}}$

Sum of interior angles of the triangle = 180°

90°+30°+y°=180°

120°+ y°=180°

y°=180°-120°

y°=60°

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${\blue{\bold{\text{Hope it helps}}}}$