Please answer this question I really want the answer
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Hey
Here is your answer,
Given (a+1/a) 2 = 3
Therefore (a + 1/a) = √3
Recall the formula, (a3 + b3) = (a + b)3 - 3ab(a + b)
Therefore, (a3 + 1/a3) = (a + 1/a)3 - 3 x a x 1/a (a + 1/a)
= (√3)3 - 3(√3) = 3√3 - 3(√3 = 0
Hope it helps you!
km7594604pc9kdp:
for sure
Answered by
0
Heya !!
( a + 1/a )² = 3
a + 1/a = √3
Cubing on both sides ,
( a + 1/a )³ = (√3)³
a³ + 1/a³ + 3 a × 1/a ( a + 1/a ) = 3√3
a³ + 1/a³ + 3 × √3 = 3√3
a³ + 1/a³ = 3√3 - 3√3
a³ + 1/a³ = 0.
( a + 1/a )² = 3
a + 1/a = √3
Cubing on both sides ,
( a + 1/a )³ = (√3)³
a³ + 1/a³ + 3 a × 1/a ( a + 1/a ) = 3√3
a³ + 1/a³ + 3 × √3 = 3√3
a³ + 1/a³ = 3√3 - 3√3
a³ + 1/a³ = 0.
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