please answer this question i will mark it as brainiest
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the agent angles in a parallelogram are supplementary.
so, 3x-4+3x+16=180
6x+12=180
6x=168
x=28
the angles are
1)3x-4=3(28)-4=80 degree
2)3x+16=3(28)+16=100 degree
hope this helps you
pls mark brainliest
so, 3x-4+3x+16=180
6x+12=180
6x=168
x=28
the angles are
1)3x-4=3(28)-4=80 degree
2)3x+16=3(28)+16=100 degree
hope this helps you
pls mark brainliest
shaiksofi1995:
thanks bro
Answered by
1
given angle 1 ...(3x-4)
angle 2....( 3x+16)
now , as we know sum of adjacent angles is 180
so, angle 1 + angle 2 =180
(3x-4) + (3x+16) =180
3x - 4 +3x + 16=180
3x +3x -4 +16=180
6x +12=180
6x=180-12
6x=168
x =168/6
x=28
now , angle 1=3*28-4
=84-4
=80
angle 2= 3*28+16
=84+16
=100
so as we know opposite angles of parallelogram are equal so the four angles are 1. 80
2. 100
3. 80
4. 100
angle 2....( 3x+16)
now , as we know sum of adjacent angles is 180
so, angle 1 + angle 2 =180
(3x-4) + (3x+16) =180
3x - 4 +3x + 16=180
3x +3x -4 +16=180
6x +12=180
6x=180-12
6x=168
x =168/6
x=28
now , angle 1=3*28-4
=84-4
=80
angle 2= 3*28+16
=84+16
=100
so as we know opposite angles of parallelogram are equal so the four angles are 1. 80
2. 100
3. 80
4. 100
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