Question

Please answer this question I will mark you as brainliest.........

Answer 1

$\large{\boxed{\bold{Answer:}}}$

In Δ DAC,

AD = AC (Given)

∠ADC = ∠ACD (Angles opposite to equal

sides of Δ are equal)

Now,

∠ADC is an exterior angle of ΔABD

=> ∠ADC > ∠ABD

or, ∠ACD > ∠ABD

or, ∠ACB > ∠ABC

=> AB > AC (sides opposite to greater ∠ is

larger)

AB > AD (∵ AD = AC)

$\large{\boxed{\bold{Hope\:it\:helps\:you!}}}$