PLEASE ANSWER THIS QUESTION
If P and Q can complete a certain work in 28 days and 56 days, respectively. P works for 7 days, and then Q joins P. In how many more days, can they complete the work?
BRAINLIEST QUESTION
Answers
Work of P in one day = 1/28
Work of Q in one day = 1/56
Total work of P and Q in one day
= 1/28 + 1/56 = (2+1)/56 = 3/56
7 days work of P
= 7× 1/28 = 1/4
Remaining work = 1-1/4 = 3/4
Days required for completion of work
= 3/4 ÷ 3/56
=3/4×56/3
=56÷4=14 days
And total days = 14+7 = 21
14days more are required to complete the work
Given work done by P in 1 day = (1/28).
Given work done by Q in 1-day = (1/56).
Work done by P and Q in 1 day = (1/28 + 1/56) = (2 + 1)/56 = (3/56)
So, complete work can be done in (56/3) days.
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Given that P works for 7 days.
Amount of work done by P in 7 days = (1/28) * 7
= > 1/4.
Remaining work = (1 - 1/4) = 3/4
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Hence,
The total work can be completed in = (3/4) * (56/3)
= 14 days.
Therefore, they will take 14 days to complete the work.
Hope this helps!