Question

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Answer 1

Let the total no. of pages of the book be $x.$

So Reemu read $\dfrac{x}{5}$ pages of the book and if she reads 40 pages more, she will complete $\dfrac{7x}{10}$ pages of the book.

Thus,

$\longrightarrow \dfrac{x}{5}+40=\dfrac{7x}{10}$

$\longrightarrow\dfrac{7x}{10}-\dfrac{x}{5}=40$

$\longrightarrow\dfrac{7x}{10}-\dfrac{2x}{10}=40$

$\longrightarrow\dfrac{5x}{10}=40$

$\longrightarrow\dfrac{x}{2}=40$

$\longrightarrow x=80$

So the page contains a total of 80 pages.

No. of pages left in the book to be read,

$\longrightarrow n=x-\dfrac{7x}{10}$

$\longrightarrow n=\dfrac{10x}{10}-\dfrac{7x}{10}$

$\longrightarrow n=\dfrac{3x}{10}$

$\longrightarrow n=\dfrac{3}{10}\times80$

$\longrightarrow\underline{\underline{n=24}}$

Hence 24 is the answer.

Answer 2

Answer:

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From the question it is given that,

Reemu read (1/5)th pages of a book.

• Let us assume the total number of pages in the book be ‘P’.

Then, number of pages read by Reemu

= (1/5) of P

= (1/5) × P

And also it is given the question,

If she reads further 40 pages, she would have read (7/10)th pages of the book. = (7/10) × P

So, ((1/5) × P) + 40 = (7/10) × P

(P + 200)/5 = (7P/10)

By cross mutliplication we get,

=> 2P + 400 = 7P 5P

= 400 P

= 400/5

… [divide both numerator and denominator by 5]

=>P = 80

Then, pages read by Reema = Total pages – Pages read

=>P – (7P/10) = (3P/10)

=>(3/10) × 80

=24 pages

Therefore, 24 pages are left to be read.