Question

please answer this question,its a class 11nth question ,dont. spam❌​

Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{\bigg( - 2 - \frac{ \iota}{ 3} \bigg)^{3} = \frac{ - 22}{3} + \bigg( \frac{ - 11 \iota}{3} \bigg)}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given :}} \\ \tt: \implies \bigg( - 2 - \frac{ \iota}{ 3} \bigg)^{3} \\ \\ \red{\underline \bold{To \: Find :}}\\ \tt: \implies In \: form \: of \: (a + \iota b) =?$

• According to given question :

$\bold{As \: we \: know \: that} \\ \tt: \implies \bigg( - 2 - \frac{ \iota}{ 3} \bigg)^{3} \\ \\ \tt \circ (a - b)^{2} = {a}^{3} - {b}^{3} - 3ab(a - b) \\ \\ \tt: \implies { (- 2)}^{3} - \bigg(\frac{ \iota}{3} \bigg)^{3} - 3 \times ( - 2) \times \frac{ \iota}{3} \bigg( - 2 - \frac{ \iota}{3} \bigg) \\ \\ \tt \circ \: { \iota}^{3} = - \iota \\ \\ \tt: \implies - 8 - \bigg( \frac{ - \iota}{3} \bigg) + 2 \iota \bigg( \frac{ - 6 - \iota}{3} \bigg) \\ \\ \tt: \implies - 8 + \frac{ \iota}{3} - \frac{12 \iota - 2 {\iota}^{2} }{3} \\ \\ \tt \circ \: \iota^{2} = - 1 \\ \\ \tt: \implies \frac{ - 24 + \iota - 12 \iota - 2 \times - 1}{3} \\ \\ \tt: \implies \frac{ - 22 - 11 \iota}{3} \\ \\ \green{\tt: \implies \bigg( - 2 - \frac{ \iota}{ 3} \bigg)^{3} = \frac{ - 22}{3} + \bigg( \frac{ - 11 \iota}{3} \bigg)}$

Answer 2

Answer:

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