Please answer this question no. 2
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sunny11216:
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The area of each triangular wall
=1/2×base×height
Base=120m
Height=22m
Then area =(120×22)÷2=1320 sq. m
Given in the question is that per sq. m yields ₹5000/year i. e. for 3 months per sq. m would yield 5000×3/12=₹1250/sq. m
Total revenue generated from one of the walls is,
₹1250×1320=₹16,50,000/-
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#Be Brainly✌️
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The area of each triangular wall
=1/2×base×height
Base=120m
Height=22m
Then area =(120×22)÷2=1320 sq. m
Given in the question is that per sq. m yields ₹5000/year i. e. for 3 months per sq. m would yield 5000×3/12=₹1250/sq. m
Total revenue generated from one of the walls is,
₹1250×1320=₹16,50,000/-
---------------------------
#Be Brainly✌️
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1
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