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5
x+y)^2 =4
x^2 +y^2 +2xy =4
x^2 +y^2 + xy +xy =4 ..........2)
÷÷÷÷÷÷÷÷÷÷÷÷÷÷÷÷÷÷÷
from first equation
÷÷÷÷÷÷÷÷÷÷÷
X^2+y^2 + xy =1. put it in 2)
1+xy =4
xy =4
hope it help you dear
x^2 +y^2 +2xy =4
x^2 +y^2 + xy +xy =4 ..........2)
÷÷÷÷÷÷÷÷÷÷÷÷÷÷÷÷÷÷÷
from first equation
÷÷÷÷÷÷÷÷÷÷÷
X^2+y^2 + xy =1. put it in 2)
1+xy =4
xy =4
hope it help you dear
ck233:
kons question puchha hai
Answered by
5
The answer is option(D) - x^3.
Hope this helps!
Hope this helps!
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