Question

A body freelly falling from rest has a velocity V after it falls a height H . The distance it has to fall for its velocity to become double is

Answer 1

wen it falls from a height h
the velocity of reach Is given by v=√2gh
now v'=2v
means v'=2√2gh or √8gh
v'/v=√8gh/√2gh
hence..height must be 4h