A body freelly falling from rest has a velocity V after it falls a height H . The distance it has to fall for its velocity to become double is
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wen it falls from a height h
the velocity of reach Is given by v=√2gh
now v'=2v
means v'=2√2gh or √8gh
v'/v=√8gh/√2gh
hence..height must be 4h
the velocity of reach Is given by v=√2gh
now v'=2v
means v'=2√2gh or √8gh
v'/v=√8gh/√2gh
hence..height must be 4h
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