Math, asked by shreyaanand, 1 year ago

please answer this question on a sheet of paper with full steps otherwise your answer will be reported no spamming please. 8-)

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Answered by pulkitraina260ovri2y
1

area =  \frac{1}{2}  {x}^{2}  + 2x +  \frac{3}{2}  \\ so \\  \frac{1}{2}  \times  d_{1} \times  d_{2} =   \frac{1}{2}  ( {x}^{2}  + 4x + 3) \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  =  \frac{1}{2} ( {x}^{2} + 3x + x + 3) \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:    \:   =  \frac{1}{2} (x + 1)(x + 3) \\ so \\  d_{1} \times  d_{2} = (x + 1)(x + 3) \\ so \: smaller \: diagonal \: is \: (x + 3)
please mark brainliest

shreyaanand: can't as only u have answered
pulkitraina260ovri2y: you can after some time
pulkitraina260ovri2y: so pls. whenever possible do it
shreyaanand: ya okkkkk
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