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let the length of the journey be x
so,
in distance,
first part=x/3
second part=x/3m
third part=x/3m
in time,
1st=x/(3×2)=x/6s
2nd=x/(3×3)=x/9s
3rd=x/(3×6)=x/18s
so,
avg velocity
=(x/3+x/3+x/3)/(x/6+x/9+x/18)
=(3x/3)/[(3x+2x+x)/18]
=x/(6x/18)
=x/(x/3)
=3m/s
so,
in distance,
first part=x/3
second part=x/3m
third part=x/3m
in time,
1st=x/(3×2)=x/6s
2nd=x/(3×3)=x/9s
3rd=x/(3×6)=x/18s
so,
avg velocity
=(x/3+x/3+x/3)/(x/6+x/9+x/18)
=(3x/3)/[(3x+2x+x)/18]
=x/(6x/18)
=x/(x/3)
=3m/s
ReetChauhan1112:
hope it helped
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