Math, asked by athishvaishu123, 5 hours ago

please answer this question please​

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Answers

Answered by CopyThat
8

Answer :-

The values of x and y are 2 and -8.

Step-by-step explanation :-

Given :

If {2\left[\begin{array}{ccc}3&4\\5&x\end{array}\right]} + \left[\begin{array}{ccc}1&y\\0&1\end{array}\right] = \left[\begin{array}{ccc}2&0\\10&5\end{array}\right].

To find :

Values of x and y ?

Solution :

{2\left[\begin{array}{ccc}3&4\\5&x\end{array}\right]} + \left[\begin{array}{ccc}1&y\\0&1\end{array}\right] = \left[\begin{array}{ccc}2&0\\10&5\end{array}\right]

\left[\begin{array}{ccc}6&8\\10&2x\end{array}\right] + \left[\begin{array}{ccc}1&y&\\0&1\end{array}\right] = \left[\begin{array}{ccc}2&0\\10&5\end{array}\right]

\left[\begin{array}{ccc}6+1&8+y\\10+0&2x+1\end{array}\right] = \left[\begin{array}{ccc}2&0\\10&5\end{array}\right]

Now,

[8 + y] = 0

[2x + 1] = 5

We get,

8 + y = 0

y = 0 - 8

∴ y = -8

2x + 1 = 5

2x = 4

∴ x = 2

∴ The values of x and y are 2 and -8.

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