Question

please answer this question please

Answer 1

the required ratio is 3:2.

Let the shopkeeper mixed x litre of mustard oil with y litre of other type of oil.
so, total CP = Rs ( 100x + 50y )
SP = Rs 96(x+y)
By the given condition,
(100x + 50y) + 20% of (100x + 50y) = 96(x+y)
Now by solving this equation you will get that
x:y = 3:2

hope this anwer will help you....

Answer 2

Given Selling price = 96, Profit = 20%.

We know that Cost price = (100/100 + Gain%) * SP

⇒ (100/120) * 96

⇒ (9600/120)

⇒ 80.

Let, the quantity of pure mustard oil be x and the quantity of other oil be y.      

⇒ 100x + 50y = 80     ------ (1)

⇒ x + y = 1.      -------- (2)

On solving (1) & (2) * 50, we get

⇒ 100x + 50y = 80

⇒ 50x + 50y = 50

    -------------------------

     50x = 30

      x = 30/50

      x = 3/5.

Substitute x = 3/5 in (2), we get

⇒ x + y = 1

⇒ (3/5) + y = 1

⇒ y = 1 - 3/5

⇒ y = 2/5.

Now,

⇒ x/y

⇒ (3/5) * (5/2)

⇒ 3/2.

Ratio of x to y is  3:2.

Therefore, the ratio in which he mixed the two oil is 3:2.

Hope this helps!