Question

please answer this question pls​

Answer 1

it will 9.8m/s as the value is equal to the acc due to gravity

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Answer 2

Answer:

answer will be 9.8 m/s as per my calculations

a = -9.8 m/$s^{2}$

v = 0 m/s

u = 49 m/s

v = u + at

=> 0 = 49 + (-9.8t)

=> 0 - 49 = -9.8t

=> t = $\frac{-49}{-9.8}$

=> t = 5 sec

We have to find the value of v' 1 sec before reaching the max h

t' = 4 sec

let v' = y

u = 49 m/s

a = -9.8 $m/s^2$

v' = u + at

v' = 49 + (-9.8×4)

v' = 49 - 39.2

v' = -9.8

The minus sign just means that it is in opposite direction. So the answer can either be 9.8 m/s or -9.8 m/s

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