Math, asked by Mehakdeep1, 11 months ago

please answer this question quickly.​

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Answered by Anonymous
1

Hii its tom85

y= x[(cos^2x/2 - sin^2x/2)+ sinx] +1/2sqrtx

y=x{cosx + sinx } + 1/2sqrtx

differentiating with respect to X

dy/dx = x(-sinx + cosx ) + sinx + cosx - 1/4sqrtx

dy/dx = (1- x)sinx + (1 + x)cosx -1/4sqrtx

none of these

option 4

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hope it may helps you

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