Question

please answer this question quickly.​

Answer 1

Answer:

(A)

(1)

$\frac{1}{rp} = \frac{1}{10} + \frac{1}{40} \\ \frac{1}{rp} = \frac{4 + 1}{40} \\ \frac{1}{rp} = \frac{5}{40} \\ rp = 8 \: ohm$

(2)

$\frac{1}{rp} = \frac{1}{30} + \frac{1}{20} + \frac{1}{60} \\ \frac{1}{rp} = \frac{2 + 3 + 1}{60} \\ \frac{1}{rp} = \frac{6}{60} \\ rp = 10$

Total resistance: 10 + 8 = 18 ohm

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(B)

I = V / R

I = 12 v / 18 ohm

I = 0.67 A

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Answer 2

Answer:

18Ω ; 0.66A

Explanation:

R1 & R2 are in parallel hence.....

R' = R1 R2 / (R1 + R2) = 10 × 40 /(10 + 40)

R' = 8Ω

R3, R4 & R5 are in parallel hence.....

1/R" = 1/R1 + 1/R2 + 1/R3

1/R" = 1/30 + 1/20 + 1/60

1/R" = 1/10

R" = 10Ω

R' & R" are in series...hence....

R = R' + R" = 8 + 10

(a) Total Resistance : R = 18Ω

current i = V/R

i = 12 / 18

(b) total current flow i = 0.66A