Please answer this question step by step for 50 points.
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Correct answer is C but explain the answer.
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First of all name all the resistors
R1,R2,R3,R4,R5,R6,R7
and then keep those resistors which are joined by wire in parallel and calculate the resistance of first three resistor
1/R=1/R1+1/R2+1/R3
1/R=3/R
R=R/3
nd now the last thre resistors in parallel
R=R/3
then join the middle resistor R4 and both the equivalent resistance R/3 and R/3 in series then
R eq.= R/3+R/3+R
R=5R/3
this is the answer
if u r satisfied then mark it as the brainliest
thank you
R1,R2,R3,R4,R5,R6,R7
and then keep those resistors which are joined by wire in parallel and calculate the resistance of first three resistor
1/R=1/R1+1/R2+1/R3
1/R=3/R
R=R/3
nd now the last thre resistors in parallel
R=R/3
then join the middle resistor R4 and both the equivalent resistance R/3 and R/3 in series then
R eq.= R/3+R/3+R
R=5R/3
this is the answer
if u r satisfied then mark it as the brainliest
thank you
Answered by
0
Here is your answer in the attachment
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